Reactant engrossment and Rate of Reaction Aim: See rascal 82 Exploring chemistry Stage 2 Equipment: See rascal 82 Exploring chemical science Stage 2 physical process: See page 82 Exploring Chemistry Stage 2 Discussion: Study of rate of chemical chemical reaction betwixt atomic number 11 Thiosulfate and HCl, the rate is slower when diluted because the water particles tie the sodium thiosulfate particles to become more dispersed and so in that take note are less successful collisions at their activation muscularity mean it takes long-term for the southward particles to be produced and thus it takes longer for the source to turn cloudy. Safety: Hydrochloric acid sulphur dioxide (produced in this reaction if asthmatic then keep your distance) Observations: Before essay: The sodium thiosulphate was a pallid solution. The hydrochloric acid was also a colourless solution. During Experiment: The sodium thiosulphate reacted with the hydrocloric acid to make a reaction mixture that set outs more cloudy as yellow-bellied sulphur is create After Experiment: The sodium thiosulphate and hydrochloric acid has reacted and organize a yellow substance (sulphur dioxide). Results: Vol of 0.25 gram molecule/L Na2S2O3 (mL) Vol of water system added (mL) Total Vol after adding and mixing 5 mL HCl Concentration of Na2S2O3 on mixing (mol/L) Time for deflower to disappear (s) 1 Time (s-1) 45 0 50 0.225 22 0.045 35 10 50 0.175 27 0.037 25 20 50 0.125 34 0.029 15 30 50 0.075 49 0.020 5 40 50 0.025 328 0.
00309 Reaction: sodium thiosulphate! »» Sulphur + Sodium Chloride + Sulphur Dioxide + water system NA2S2O3 + 2HCL »» S + 2NaCl + SO2 + H2O (aq) + (aq) »» (s) + (aq) + (g) + (l) Calculations: (C)(V)= (C)(V) (1.25)(45) = (C)(50) C = (0.25)(45) (50) C = 11.25 50 C = 0.225 mol/L Conclusion: As the concentration of Sodium...If you want to get a full essay, order it on our website:
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